So 1 day extra should be Friday. b. Solution: c. The formed number using the digits 1, 2, 3, 4 and 5 if it has to be divisible by 4, has to have the last two digits 12 or 24 or 32 or 52. Let X be the event that A is selected and Y is the event that B is selected. I = event that the friend is selected. X speaks truth in 80% of cases and Y in 90% of cases. c. 0 The probability of X is 1/8 and that of Y is 2/5. b. If a pen is drawn at random from the pack, replaced and the process is repeated 2 more times, what is the probability of drawing 2 blue pens and 1 black pen? Then P(X) = 80/100 = 4/5 d. 1/12 Solution: b. Solution: b, Total no. As there is two E’s. c. 5/13 d. 3/17, Probability                    =  [ Favourable outcomes]/ Total, Box 1 has a total of                 = 2+4 = 6 shirts, Probability of white from box1 = 4/6 = 2/3, So box 2 has (2+1)                  = 3 white and 4 blue shirts, Total in box 2                           = 3+4 = 7, So white shirt probability from box 1 and 2 = 2/3*3/7, Probability of blue from box 1 = 2/6= 1/3, So box 2 has (4+1)                  = 2 white and 5 blue shirts, Total in box 2                           = 2+5 = 7, So white shirt probability from box 1 and 2 = 1/3*2/7, Total probability                                        = 2/7+2/21, 5. The frequency of a tyre required to be replaced before covering 4000 km = 20, (ii) The frequency that tyre will last more than 9000 km = 325 + 445 = 770. 3. 5/7 21. a. Outcomes: A possible result of a random experiment. Taking two E’s as one letter, number of ways of arrangement in which both E’s are together =9! a. a. 1/450 If a card is chosen in random from this set, find the possibility of choosing a yellow card or an ‘IMPORTANT’ card? … P(X-lie) = 1−4/5 = 1/5 You toss a coin AND roll a dice. d. 3/8 In a certain state’s lottery, 48 balls numbered 1 through 48 are placed in a machine and six of them … Explanation: Let A, B, C be the respective events of solving the problem and A , B, C be the respective events of not solving the problem. a. c. 1/12 a. Let E be the event the card drawn is ace. In this post, we will be learning about Probability questions and answers. Then A, B, C are independent event. One shirt is picked in random and is put in another basket. = (4/5*1/10) + (1/5*9/10) For the formula application, please refer to Section B. Hence, a number divisible by 4 can be formed in 6×4=24 ways. The Complete number that can be formed using the digits 1, 2, 3, 4 and 5 without repetition =5!= 5*4*3*2*1=120, 16.A lucky draw is held to select a student who will live in the only luxury room in a hostel. A man and his friend applied for the same post in a company. b. An event with a probability of ZERO can be considered impossible: for example, the probability that the coin will land on the ground without either of the sides facing up is 0, because there must be either head or tail must be facing up. Sum of probabilities of all elementary events of a random experiment is 1. 46/250 b. 1/70 The questions here will cover the basics as well as the hard level problems for all levels of students. c. 7/18 The chances of getting a tail in one toss = 1/2. With Example, Session And Presentation Layer Protocol Tutorial With Example, Section A – This section contains important formulas, short tricks, concepts on Probability. c. 4/17 Probability of drawing another blue pen = 3/9 b. c. 17/20 Our required event is (T,T) whose occurrence is only once out of four possible outcomes and so, our answer is 1/4. It is a state of probability. c. 16/35 a. b. Two coins (a one rupee coin and a two rupee coin) are tossed once. 1/25 11/50 Solution. Therefore, it is a very important chapter. For example, when a test is conducted, then the student can either get a pass or fail. The probability of happening of an event E is a number P(E) such that: Probability Formula: If an event E occurs, then the empirical probability of an event to happen is: P(E) = Number of trials in which Event happened/Total number of trials. What is the probability of getting a prize if a card is taken at random? a. 26% = P(X).P(Y-lie) + P(X-lie).P(Y) c. 1/480 b. 4/3 What is the probability that the ticket taken is a multiple of 2 or 5? Two dice are rolled, find the probability that the sum is. P(A or B) = P(A) + P(B) – P(A and B). So, the probability is 0. In a lucky draw, there are 15 prizes and 20 blank cards. Probability Example 1. Let E = event of getting a multiple of 2 or 5 Find a sample space. Solution: Let us say the events of getting two heads, one head and no head by E1, E2 and E3, respectively. 2/30 d. 9/13 b. Your email address will not be published. What is the probability of getting a head and a 5 on the dice? a. What is the probability that only one of them will be selected? Now, X and Y contradict each other = [X lies and Y true] or [Y true and Xlies] What is the percentage of cases that X and Y are likely to contradict each other, narrating the same incident? 29/72 c. 50% a. An apple is drawn and then another apple is drawn without replacement. Y = Event that Y speaks the truth Solution: c, Total names in the lucky draw= 4×200+3×250+2×100, 17. d. 5/3 The probability of an event is given by – The Number Of Ways Event A Can Occur The total number Of Possible Outcomes So for example if there are 4 red balls and 3 yellow balls in a bag, the probability of choosing a red ball will be 4/7 Such an event is called an impossible event. Calculate the probability that the card will. Two brothers A and B appeared for an exam. Solution: c, In two throws of a dice, n(S) = (6×6) = 36, Let E= event of getting a sum 9 = {(3,6), (4,5), (5,4), (6,3)}, 23. a. probability problems, probability, probability examples, how to solve probability word problems, probability based on area, examples with step by step solutions and answers, How to use permutations and combinations to solve probability problems, How to find the probability of of simple events, multiple independent events, a union of two events Sample Probability questions with solutions. A coin is tossed twice. Solution: In the random experiment where head can appear on the 1st toss, or the 2nd toss, or the 3rd toss and so on till we get the head of the coin. We will see many questions and answers on the topic Probability with tricks/shortcuts to solve them. c. 2/9 d. 5/20 Now,eval(ez_write_tag([[300,250],'tutorialwing_com-medrectangle-4','ezslot_2',124,'0','0'])); We recommend go through section A, then section B, then section C. Even if you are familiar with this topic, do not just skip section A and section B. Probability in mathematics deals with calculating the likelihood of a particular event’s occurrence, which is expressed as a number between 1 and 0. c. 11/40 a) equal to 1. b) equal to 4. c) less than 13. The probability of Sangeet to win = P(S) = 0.62, The probability of Rashmi to win = P(R) = 1 – P(S). 1. A pack contains 3 blue, 1 red and 5 black pens. The table shows the results of 1000 cases. ∴ A, B, C are independent events. 8/5 (iii) it has to be replaced after 4000 km and 14000 km is covered by it? The probability of the man’s selection is 1/5 and the probability of the friend’s selection is 1/8. What is the probability of the occurrence of a number that is odd or less than 5 when a fair die is rolled. Section C – Go to this section to solve some problems on Probability. c. 4/15 Let the event of the occurrence of a number that is odd be ‘A’ and the event of the occurrence of a number that is less than 5 be ‘B’. b. 1/5 Sure event: The probability of an event which is sure to occur is 1. Solution: c. There is no bulb with lifetime of 1250 hrs. Since, the apple is not replaced there are now 11 odd numbered apples and total 24 apples left. = P [(A∩Ī)or(I∩Ᾱ)]. 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