Final Kinetic Energy: using ! The graph shows how this kinetic energy varies with frequency. 6. Tes Global Ltd is Explain your answer. registered in England (Company No 02017289) with its registered office at 26 Red Lion 4.4 54 customer reviews. ANSWER KEY . London WC1R 4HQ. KE = ½ mv2 2 KE = 500J m = ? Questions for pupils to practice using and re-arranging the kinetic energy equation. This resource is designed for UK teachers. Created: Nov 27, 2011| Updated: Feb 3, 2015. This website and its content is subject to our Terms and Author: Created by PinkHelen. The maximum kinetic energy of the photoelectrons emitted from metal X is measured for a number of different frequencies of the radiation. Kinetic energy calculation questions. An archer with his bow drawn _P____ 7. View US version . Potential Difference and Current Calculations Worksheet with Answers Walking down the street __K___ 3. Questions for pupils to practice using and re-arranging the kinetic energy equation. Solution: Think back to Newton’s 1st Law. 10 lo- kinetic energy of photoelectrons/ J 5x 101 frequency/Hz (i) Use the graph to find the threshold frequency for metal X. An object moving with a speed of 67 m/s and has a kinetic energy of 500 J, what is the mass of the object. AQA GCSE Physics & Combined Science Physics Required Practical Revision 9-1, Physics Paper 1 Revision AQA Trilogy Foundation, Team Quest Christmas 2020 - Team Building Quiz for KS3. This tells us Preview. Conditions. Kinetic and Potential Energy Worksheet. Square S: the kinetic energy of the diver on the board is equal to the energy transferred to the diver when climbing the steps T: when the diver hits the water, all the gravitational potential energy is regained (Marks available: 2) 2. Classify the following as a type of potential energy or kinetic energy (use the letters K or P) 1.A bicyclist pedaling up a hill __K___ 6. What is the Kinetic Energy of a 478 kg object that is moving with a speed of 15 m/s? The wind blowing through your hair __K___ 2. v = 67m/s 2KE/v 2= m OR m = 2KE/v (rearrange equation) m = 2(500J)/(67)2 m = 1000J/4,489 m = .22 kg 7. E k = 1 2 mv2 =0.5 x (1.5x104) x (11580)2 =1.006 x 1012J so Kinetic Energy gained = final E k - initial E k = 1.006 x 1012J - 2.028 x 1011J = 8.032 x 1011J (c) If the rocket is in space and the engine is then switched off, what will happen to the rocket speed? The formulae below may be of help with parts of this question.